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Array (Example 1)
Concepts:
Arrays, initialization and utilization
Text:
Implement a C program that:
- after the declaration and the initialization of a vector of 10 elements
- finds and prints the first even number and its position in the array
Solution:
- array_1.c
/* Print the first even number and its position of a 10 elements array/vector. */ #include <stdio.h> #define SIZE 10 int main(){ int vec[SIZE] = {1, 5, 3, 7, 10, 1, 2, 3, 4, 5}; int i; int found = 0; /* First solution */ for(i=0; i<SIZE && !found; i++){ if ( vec[i]%2 == 0 ){ found = 1; } } /* Second solution */ i = 0; found = 0; while ( i<SIZE && !found ){ if ( vec[i]%2==0 ){ found = 1; } i = i + 1; } if (found){ printf("EVEN NUMBER: %d (POSITION: %d)\n", vec[i-1], i-1); } else { printf("No even number is present in array\n"); } return 0; }
Comments:
The program:
- after the initialization of an array of dimension SIZE, directly performed during the declaration:
int vec[SIZE] = {1, 5, 3, 7, 10, 1, 2, 3, 4, 5};
- it scans the array by using a for cycle until all the elements of the vector are analyzed (condition i<SIZE) and until an even number is found (the variable found has a value different than 0, i.e., true). The variable found is set to 1 when the first even number is found in the vector.
for(i=0; i<SIZE && !found; i++){ if ( vec[i]%2 == 0 ){ found = 1; } }
- the same exercise can be resolved equivalently by using the while statement:
/* Second solution */ i = 0; found = 0; while ( i<SIZE && !found ){ if ( vec[i]%2==0 ){ found = 1; } i = i + 1; }
- results are printed at the end of the program. It is important to notice that at the exit of both the for and the while cycle, the variable i is the next position of the first even number. For such reason, to print the first even element of the vector and its position the variables vec[i-1] and i-1 must be used, respectivelly.
if (found){ printf("EVEN NUMBER: %d (POSITION: %d)\n", vec[i-1], i-1); } else { printf("No even number is present in array\n"); }
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