cs:c_language:leap_year

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cs:c_language:leap_year [2018/11/20 10:54] zioskenz |
cs:c_language:leap_year [2019/02/26 14:35] |
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- | ====== Leap Year ====== | ||

- | **Concepts:**\\ | ||

- | If statement and boolean expressions | ||

- | **Text:**\\ | ||

- | Given a year (an integer number), say if it is a leap year. | ||

- | A leap year is a year: | ||

- | * divisible by 4 | ||

- | * but not by 100 | ||

- | * with the exception of the years divisible by 400, which are leap years | ||

- | |||

- | Examples: 1996, 2000 and 2100 are leap years; instead 2015, 1900 and 2100 are not leap years. | ||

- | |||

- | **Solution:**\\ | ||

- | |||

- | <file C leap year.c> | ||

- | /* | ||

- | Given a year (an integer number), say if it is a leap year. | ||

- | A leap year is divisible by 4, but not by 100. | ||

- | An exception are the years divisible by 400, which are leap years. | ||

- | */ | ||

- | |||

- | #include <stdio.h> | ||

- | |||

- | |||

- | int main(void){ | ||

- | int leap=0; | ||

- | int year; | ||

- | |||

- | printf("Insert an year: "); | ||

- | scanf("%d", &year); | ||

- | |||

- | /* First solution: base on a support varible leap */ | ||

- | if ( year%4==0 ) /* divisible by 4 */ | ||

- | leap=1; | ||

- | |||

- | if ( year%100==0 ) /* but not by 100 */ | ||

- | leap=0; | ||

- | |||

- | if ( year%400==0 ) /* but year divisible by 400 are leap years */ | ||

- | leap=1; | ||

- | |||

- | if ( leap==1 ){ | ||

- | printf("%d is a leap year\n", year); | ||

- | }else{ | ||

- | printf("%d is not a leap year\n", year); | ||

- | } | ||

- | |||

- | /* Second solution: using a boolean expression */ | ||

- | if ( (year%4==0 && year%100!=0) || year%400==0 ){ | ||

- | printf("%d is a leap year\n", year); | ||

- | }else{ | ||

- | printf("%d is not a leap year\n", year); | ||

- | } | ||

- | |||

- | return 0; | ||

- | } | ||

- | </file> |

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